A) \[SnC{{l}_{2}}\]
B) \[CC{{l}_{2}}\]
C) \[GeC{{l}_{2}}\]
D) \[PbC{{l}_{2}}\]
Correct Answer: D
Solution :
\[PbC{{l}_{2}}\]is the most stable among these, due to inert pair effect of Pb. Inert pair effect increase in a group from top to bottom and due to it, the lower oxidation state is more stable than higher oxidation state. (Thus, \[PbC{{l}_{2}}\] is stabler than\[PbC{{l}_{4}}\])
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