A) 300
B) 375
C) 150
D) 75
Correct Answer: B
Solution :
From gas equation, \[{{P}_{1}}{{V}_{1}}={{n}_{1}}\cdot R{{T}_{1}}=\frac{{{w}_{1}}}{{{m}_{1}}}\cdot R{{T}_{1}}\] ?(i) \[{{P}_{2}}{{V}_{2}}=\frac{{{w}_{2}}}{{{m}_{2}}}\cdot R{{T}_{2}}\] ?(ii) As, \[{{P}_{1}}={{P}_{2}},\] \[{{V}_{1}}={{V}_{2}}\]hence, \[{{T}_{1}}={{T}_{2}}\] Hence, \[\frac{{{w}_{1}}}{{{m}_{1}}}=\frac{{{w}_{2}}}{{{m}_{2}}}\] \[\therefore \] \[\frac{15}{30}=\frac{75}{{{m}_{2}}}\] (\[\because \] molecular weight of ethane = 30) \[\therefore \] \[{{m}_{2}}=150\] Hence, vapour density of\[{{X}_{2}}\]gas is \[=\frac{M}{2}=\frac{150}{2}=75\]
You need to login to perform this action.
You will be redirected in
3 sec
