A) \[2\times {{10}^{-11}}C\]
B) \[3\times {{10}^{-11}}C\]
C) \[5\times {{10}^{-11}}C\]
D) \[9\times {{10}^{-11}}C\]
Correct Answer: A
Solution :
Electric field due to point charge \[E=\frac{q}{4\pi {{\varepsilon }_{0}}{{r}^{2}}}\] or \[q=E\,4\pi {{\varepsilon }_{0}}{{r}^{2}}\] \[\therefore \] \[q=E\times 4\pi {{\varepsilon }_{0}}{{r}^{2}}=2\times \frac{1}{9\times {{10}^{9}}}\times {{\left( \frac{30}{100} \right)}^{2}}\] \[=2\times {{10}^{-11}}C\]
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