A) 4 times
B) 8 times
C) 1/4 times
D) 1/8 times
Correct Answer: D
Solution :
Applying Keplers law \[{{T}^{2}}\propto {{R}^{3}}\] Hence \[\frac{T_{2}^{2}}{T_{1}^{2}}=\frac{R_{2}^{3}}{R_{1}^{3}}={{\left( \frac{1}{4}\frac{{{R}_{1}}}{{{R}_{1}}} \right)}^{3}}\] or \[{{T}_{2}}={{\left( \frac{1}{4} \right)}^{3/2}}\] \[{{T}_{1}}=\frac{{{T}_{1}}}{8}\]
You need to login to perform this action.
You will be redirected in
3 sec
