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JIPMER Jipmer Medical Solved Paper-2001

  • question_answer
    A gas expands \[0.25\text{ }{{m}^{3}}\]at constant pressure \[{{10}^{3}}N/{{m}^{2}},\] the work done is:

    A)  250 N                                   

    B)  250 W                  

    C)  250 J                    

    D)         2.5 ergs

    Correct Answer: C

    Solution :

    From the formula of work done \[W=P\,\Delta V={{10}^{3}}\times 0.25=250\,J\]


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