A) \[\frac{2a{{R}^{2}}}{s}\]
B) \[\frac{2a{{s}^{2}}}{R}\]
C) \[{{\left[ 1+\left( \frac{{{s}^{2}}}{{{R}^{2}}} \right) \right]}^{1/2}}\]
D) \[2as\]
Correct Answer: D
Solution :
\[{{E}_{k}}=\frac{1}{2}m{{v}^{2}}=a{{s}^{2}}\]or \[{{v}^{2}}=\frac{2a{{s}^{2}}}{m}\] or \[2v\frac{dv}{dt}=\frac{2a}{m}2s\] So acceleration\[=\frac{2as}{m}\] Therefore force = acceleration\[\times \]mass \[=\frac{2as}{m}\times m=2as\]
You need to login to perform this action.
You will be redirected in
3 sec
