A) 2.2 M
B) 0.2 M
C) 0.5 M
D) 0.1 M
Correct Answer: B
Solution :
Molarity of glucose solution \[=\frac{\text{weight}\,\text{of}\,\text{glucose}}{\text{molecular}\,\text{weight}\,\text{of}\,\text{glucose}}\times volume\,(in\,litre)\] \[=\frac{18}{180\times \frac{500}{1000}}=0.2\,M\]
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