A) \[C{{H}_{3}}C{{H}_{2}}NHOH\]
B) \[C{{H}_{3}}COOH\]
C) \[C{{H}_{3}}C{{H}_{2}}CON{{H}_{2}}\]
D) \[C{{H}_{3}}CHO\]
Correct Answer: D
Solution :
The reaction is as follows: \[C{{H}_{3}}CN\xrightarrow[\text{reduction}]{\text{Na/}{{\text{C}}_{\text{2}}}{{\text{H}}_{\text{5}}}\text{OH}}C{{H}_{3}}C{{H}_{2}}N{{H}_{2}}\] \[\xrightarrow{HN{{O}_{2}}}\underset{\text{Ethanol}}{\mathop{C{{H}_{3}}C{{H}_{2}}OH}}\,\xrightarrow{[O]}\underset{\text{Acetaldehtde}}{\mathop{C{{H}_{3}}CHO}}\,\]
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