A) Addition of HBr to alkene
B) Friedel-Craffs reaction
C) Sandmeyer reaction
D) None of the above
Correct Answer: C
Solution :
The reaction, \[{{C}_{6}}{{H}_{5}}--N==N--Cl\xrightarrow{C{{u}_{2}}Cl/HCl}{{C}_{6}}{{H}_{5}}Cl+{{N}_{2}}\]is called Sandmeyer reaction. Its mechanism is follows \[{{C}_{6}}{{H}_{5}}{{N}_{2}}Cl\xrightarrow{{}}{{C}_{6}}{{H}_{5}}N_{2}^{+}+C{{l}^{-}}\] \[CuCl+C{{l}^{-}}\xrightarrow{{}}CuCl_{2}^{-}\] \[{{C}_{6}}{{H}_{5}}N_{2}^{+}+CuCl_{2}^{-}\xrightarrow{{}}{{C}_{6}}{{H}_{5}}+{{N}_{2}}+CuC{{l}_{2}}\] \[{{C}_{6}}{{H}_{5}}+CuC{{l}_{2}}\xrightarrow{{}}{{C}_{6}}{{H}_{5}}Cl+CuCl\]
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