A) 5 m/s
B) 1 m/s
C) 0.5 m/s
D) 10 m/s
Correct Answer: D
Solution :
Applying law of conservation or momentum \[mv\text{ }=\text{ }m\upsilon \] Here, mass of bullet \[m=50\text{ }g=0.05\text{ }kg\] velocity of bullet \[=1\text{ }km\text{/}sec=1000\text{ }m\text{/}sec\] mass of gun \[m=5kg\] or \[0.05\times 1000=5v\] or \[v=\frac{0.05\times 1000}{5}\] so, \[v=10\,m\text{/}s\]You need to login to perform this action.
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