A) \[{{C}_{2}}{{H}_{6}}\]
B) \[{{C}_{2}}{{H}_{4}}\]
C) \[C{{H}_{3}}Cl\]
D) \[{{C}_{2}}{{H}_{2}}\]
Correct Answer: D
Solution :
With the increase in s-character of hybridisation of carbon, acidity also increase. Hence, acetylene (sp-hybrid) shows acidic character and reacts with sodium metal to give sodium acetalyde. \[H--C\equiv \equiv C--H+2Na\xrightarrow{{}}\] \[2N{{a}^{+}}{{(C\equiv \equiv C)}^{2-}}+{{H}_{2}}\uparrow \]
You need to login to perform this action.
You will be redirected in
3 sec
