A) \[PC{{l}_{5}}(g)\rightleftharpoons PC{{l}_{3}}(g)+C{{l}_{2}}(g)\]
B) \[2S{{O}_{2}}(g)+{{O}_{2}}(g)\rightleftharpoons 2S{{O}_{3}}(g)\]
C) \[{{N}_{2}}{{O}_{4}}(g)\rightleftharpoons 2N{{O}_{2}}(g)\]
D) \[{{H}_{2}}(g)+{{I}_{2}}(g)\rightleftharpoons 2HI(g)\]
Correct Answer: D
Solution :
\[{{K}_{p}}={{K}_{c}}{{(RT)}^{\Delta {{n}_{g}}}}\] where, \[\Delta {{n}_{g}}=\] number of moles of gaseous products-number of moles of gaseous reactants. Hence, for \[{{K}_{p}}\] to be equal to \[{{K}_{c}},\]\[\Delta {{n}_{g}}\] should be zero. For the reaction, \[{{H}_{2}}(g)+{{I}_{2}}(g)\rightleftharpoons 2\,HI(g)\] \[\Delta {{n}_{g}}=2-2=0\] Hence, \[{{K}_{p}}={{K}_{c}}\,.\,\,{{(RT)}^{0}}={{K}_{c}}\]
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