A) \[{}_{15}{{P}^{30}}\]
B) \[{}_{14}S{{i}^{29}}\]
C) \[{}_{14}{{P}^{31}}\]
D) \[{{P}^{\,+}}\]
Correct Answer: C
Solution :
Isotones are the species having equal number of neutrons. Hence, isotone of \[{}_{14}S{{i}^{30}}(n=16)\] is\[{}_{15}{{P}^{31}}(n=31-15=16)\].
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