A) \[{{I}_{2}}\]
B) \[C{{l}_{2}}\]
C) \[S{{O}_{2}}\]
D) \[\text{dil}\text{.}\,{{H}_{2}}S{{O}_{4}}\]
Correct Answer: A
Solution :
Among the halogens, the element, placed above in the group, can displace the halogen (placed below in group) from its solution, hence, chlorine can displace bromine from \[{{H}_{2}}{{O}_{2}}\]. \[2KBr+C{{l}_{2}}\xrightarrow{{}}2KCl+B{{r}_{2}}\]
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