JIPMER Jipmer Medical Solved Paper-1998

  • question_answer
    Ratio of rotational and tranglatory energies of a sphere is:

    A)  2/3                       

    B)         2/5                       

    C)  2/7                       

    D)         2/9

    Correct Answer: B

    Solution :

    The translational kinetic energy of a sphere is \[{{K}_{T}}=\frac{1}{2}m{{\upsilon }^{2}}\] and rotational kinetic energy of a sphere is                                 \[{{K}_{R}}=\frac{1}{2}I{{\omega }^{2}}=\frac{1}{2}\times \frac{5}{2}m{{r}^{2}}\times {{\left( \frac{\upsilon }{r} \right)}^{2}}\]                 \[{{K}_{R}}=\frac{5}{4}m{{v}^{2}}\]          \[\left( \begin{align}   & \because \,v=r\omega  \\  & \,\,I=\frac{5}{2}m{{r}^{2}} \\ \end{align} \right)\] Hence, \[\frac{{{K}_{T}}}{{{K}_{R}}}=\frac{\frac{1}{2}m{{\upsilon }^{2}}}{\frac{5}{4}m{{\upsilon }^{2}}}=\frac{1}{2}\times \frac{4}{5}=\frac{2}{5}\]


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