A)
6.0 V
B) 4.0 V
C) 3.4 V
D) 2.4 V
Correct Answer: A
Solution :
From the figure the resistance \[40\,\Omega \] and \[60\,\Omega \] are connected in parallel combination. Hence their equivalent resistance \[R=\frac{60\times 40}{60+40}=24\,\Omega \] Hence current in the circuit is \[I=\frac{E}{R+r}=\frac{6}{24+0}=\frac{6}{24}=\frac{1}{4}A\] Now potential difference across voltmeter \[=I\times R=\frac{1}{4}\times 24=6.0\,V\]
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