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JIPMER Jipmer Medical Solved Paper-1998

  • question_answer
    In a p-n-p transistor working as common base amplifier, current gain is 0.96 and emitter current is 7.2 mA. Then base current will be:

    A)  0.2 mA     

    B)                         0.29 mA              

    C)         0.35 mA              

    D)         0.4 mA

    Correct Answer: B

    Solution :

    Here, current gain \[\alpha =0.96\] and emitter current \[{{i}_{e}}=7.2\,mA\] from the relation of current gain \[\alpha =0.96=\frac{{{I}_{c}}}{{{I}_{e}}}=\frac{{{I}_{c}}}{7.2},\] So           \[{{I}_{c}}=0.96\times 7.2=6.91\,mA\] Hence the base current \[{{I}_{b}}={{I}_{e}}-{{I}_{c}}=7.2-6.91=0.29\,mA\]


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