A) directly proportional to\[\sqrt{m}\]
B) directly proportional to \[\frac{1}{\sqrt{m}}\]
C) directly proportional tom
D) independent of m
Correct Answer: D
Solution :
Not Available Using the conservation of angular momentum \[{{I}_{1}}{{\omega }_{1}}={{I}_{2}}{{\omega }_{2}}\] Here \[{{\omega }_{1}}=\omega ,\] \[{{\omega }_{2}}=?\] \[\frac{M{{r}^{2}}\cdot \omega }{2}=\left( \frac{M+m+m}{2} \right){{r}^{2}}\omega \] So, \[{{\omega }_{2}}=\frac{M\omega }{M+2m}\]
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