JIPMER Jipmer Medical Solved Paper-1998

  • question_answer
    A thin circular ring of mass M and radius r is rotating about an axis passing through its centre and perpendicular to its plane with a constant angular velocity\[\omega .\] Two objects, each of mass in are attached gently to the opposite ends of a diameter of the ring. The ring now rotates with angular velocity:

    A)  \[\frac{\omega (M-2m)}{M+2m}\]

    B)                         \[-\omega M-m\]          

    C)         \[\frac{\omega (M+2m)}{M}\]

    D)         \[\frac{\omega M}{M+2m}\]

    Correct Answer: D

    Solution :

    Using the conservation of angular momentum \[{{I}_{1}}{{\omega }_{1}}={{I}_{2}}{{\omega }_{2}}\] Here      \[{{\omega }_{1}}=\omega ,\]                    \[{{\omega }_{2}}=?\] \[\frac{M{{r}^{2}}\cdot \omega }{2}=\left( \frac{M+m+m}{2} \right){{r}^{2}}\omega \] So,          \[{{\omega }_{2}}=\frac{M\omega }{M+2m}\]


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