A) propanol
B) propanal
C) propenal
D) propanone
Correct Answer: D
Solution :
Propyne, on hydrolysis with \[HgS{{O}_{4}}\] and dil. \[{{H}_{2}}S{{O}_{4}},\] gives propanone. \[C{{H}_{3}}-C\equiv CH+{{H}_{2}}O\xrightarrow[dil.\,{{H}_{2}}S{{O}_{4}}]{HgS{{O}_{4}}}\] \[C{{H}_{3}}-\underset{OH}{\mathop{\underset{|}{\mathop{C}}\,}}\,=C{{H}_{2}}\underset{\text{tautomerise}}{\longleftrightarrow}\underset{\begin{smallmatrix} \text{Propanone-2} \\ \,\,\,\,\,\,\text{(acetone)} \end{smallmatrix}}{\mathop{C{{H}_{3}}-\underset{O}{\mathop{\underset{||}{\mathop{C}}\,}}\,-C{{H}_{3}}}}\,\]
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