A) 50.1
B) 60.1
C) 55.1
D) 45.1
Correct Answer: C
Solution :
We know that, 1 mole of a gas occupy 22.4 litre volume at S.T.P. Hence, \[{{P}_{1}}=1\,atm,\]\[{{P}_{2}}=0.5\,atm,\]\[{{V}_{1}}=22.4\,litre\] \[{{V}_{2}}=?,\]\[{{T}_{1}}=273\,K,\]\[{{T}_{2}}=335\,K\] From gas equation, \[\frac{{{P}_{1}}\,{{V}_{1}}}{{{T}_{1}}}=\frac{{{P}_{2}}{{V}_{2}}}{{{T}_{2}}}\] or \[\frac{1\times 22.4}{273}=\frac{0.5\times {{V}_{2}}}{335}\] or \[{{V}_{2}}=\frac{22.4\times 335}{0.5\times 273}\] \[=55.0\approx 55.1\,\,\text{litre}\]
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