A) \[2\pi A\]
B) \[\pi A\]
C) \[\frac{\pi A}{2}\]
D) \[\frac{\pi A}{4}\]
Correct Answer: C
Solution :
Here: Amplitude of the wave = A Maximum velocity \[{{\upsilon }_{1}}=4\upsilon \] (where \[\upsilon \] is velocity of wave) Maximum velocity relation is given by as \[{{\upsilon }_{1}}=a\omega \] or \[\omega =\frac{4\upsilon }{A}\] ?(i) Hence, wavelength of the wave \[\lambda =\frac{\upsilon }{f}=\frac{\upsilon }{\omega /2\pi }=\frac{2\pi \upsilon }{\omega }\] \[\left( \because \,f=\frac{\omega }{2\pi } \right)\] \[=\frac{2\pi \upsilon }{\frac{4\upsilon }{A}}=\frac{\pi A}{2}\] [from eq. (i)]
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