A) \[0.002\text{ }kg\text{ }{{m}^{2}}\]
B) \[0.02\text{ }kg\text{ }{{m}^{2}}\]
C) \[0.2\text{ }kg\text{ }{{m}^{2}}\]
D) \[2kg{{m}^{2}}\]
Correct Answer: C
Solution :
Here: mass m = 0.4 kg and radius r = 100 cm = 1 m The moment of inertia of the disc \[=\frac{1}{2}m{{r}^{2}}\] \[=\frac{1}{2}\times 0.4\times {{(1)}^{2}}=0.2\,kg\,{{m}^{2}}\]
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