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JIPMER Jipmer Medical Solved Paper-1997

  • question_answer
    A ball of mass 0.2 kg moves with the velocity of 20 m/sec and it stops-in 0.1 sec, then the force on the ball is :

    A)  4 N                                       

    B)  2 N                       

    C)         40 N                     

    D)         20 N

    Correct Answer: C

    Solution :

    Using relation \[v=u+at\]          [Here: \[\upsilon =20\,m/s\] \[20=0+0.1a\]                    \[u=0\]                 So,          \[a=200\,m\text{/}{{s}^{2}}\]                     \[t=0.1\,\,\sec \]] Again using \[F=ma=0.2\times 200=40\text{ }N\]


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