question_answer

The moment of inertia of thin circular disc is\[0.1\text{ }kg\text{ }{{m}^{2}}\]. The torque required to produce in the disc an angular acceleration of \[2\text{ }rad/{{s}^{2}}\]is :

A)  \[2\text{ }kg\text{ }m/{{s}^{2}}\]

B)                         \[0.2\text{ }kg\text{ }{{m}^{2}}/{{s}^{2}}\]                         

C)  4 Nm                   

D)         0.4 Nm