A) glycol
B) methanol
C) acetylene
D) two moles of \[C{{O}_{2}}\]
Correct Answer: A
Solution :
In this reaction, ethylene is oxidised to glycol. \[C{{H}_{2}}=C{{H}_{2}}\xrightarrow[(alk.)]{dil.\,KMn{{O}_{4}}}\underset{\text{Glycol}}{\mathop{C{{H}_{2}}OH-C{{H}_{2}}OH}}\,\]
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