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JIPMER Jipmer Medical Solved Paper-1995

  • question_answer
    If a 2 m long wire is moving with a velocity of 1 m/s perpendicular to a magnetic field of \[0.5\,\,wb/{{m}^{2}},\] then the emf induced in it, will be:            

    A)              2 V                                            

    B)              1 V            

    C)                     0.5 V         

    D)                                     0.2 V

    Correct Answer: B

    Solution :

    Here:     Length of wire \[l=2\,m\] Velocity of wire \[v=1\,m\text{/}s\] Magnetic field \[B=0.5\,wb\text{/}{{m}^{2}}\] As induced emf \[E=Bvl=0.5\times 1\times 2=1\,V\]


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