JEE Main & Advanced Physics Work, Energy, Power & Collision / कार्य, ऊर्जा और शक्ति JEE PYQ - Work Energy Power and Collision

  • question_answer
    Two particles of equal mass m have respective initial velocities \[u\hat{i}\]and u \[\left( \frac{\hat{i}+\hat{j}}{2} \right)\].They collide completely inelastically. The energy lost in the process is: [JEE MAIN Held on 09-01-2020 Morning]

    A) \[\sqrt{\frac{2}{3}}m{{u}^{2}}\]

    B) \[\frac{3}{4}m{{u}^{2}}\]

    C) \[\frac{1}{8}m{{u}^{2}}\]

    D) \[\frac{1}{3}m{{u}^{2}}\]

    Correct Answer: C

    Solution :

    [c] \[{{\vec{P}}_{i}}={{\vec{P}}_{f}}\]
                \[\Rightarrow mu\hat{i}+m\left( \frac{u}{2}\hat{i}+\frac{u}{2}\hat{j} \right)=\left( m+m \right)\left( {{v}_{1}}\hat{i}+{{v}_{2}}\hat{j} \right)\]
                Compare both side
                \[\Rightarrow {{v}_{1}}=\frac{3u}{4},{{v}_{2}}=\frac{u}{4}\]
                \[\Delta KE={{K}_{i}}-{{K}_{f}}\]
                \[=\frac{1}{2}m{{u}^{2}}+\frac{1}{2}m{{\left( \frac{u}{2}\sqrt{2} \right)}^{2}}-\frac{1}{2}\left( 2m \right)\left( \frac{9{{u}^{2}}}{16}+\frac{{{u}^{2}}}{16} \right)\]
                \[=\frac{m{{u}^{2}}}{8}\]


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