JEE Main & Advanced Physics Work, Energy, Power & Collision / कार्य, ऊर्जा और शक्ति JEE PYQ - Work Energy Power and Collision

  • question_answer
    A particle is released on a vertical smooth semicircular track from point X so that OX makes angle q from the vertical (see figure). The normal reaction of the track on the particle vanishes at point Y where OY makes angle \[\phi \] with the horizontal. Then: [JEE ONLINE 19-04-2014]

    A) \[\sin \phi =\cos \phi \]

    B) \[\sin \phi =\frac{1}{2}\cos \theta \]

    C) \[\sin \phi =\frac{2}{3}\cos \theta \]

    D) \[\sin \phi =\frac{3}{4}\cos \theta \]

    Correct Answer: C


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