JEE Main & Advanced Physics Wave Optics / तरंग प्रकाशिकी JEE PYQ-Wave Optics

  • question_answer
    Light wavelength \[550nm\] falls normally on a slit of width\[22.0\times {{10}^{-5}}cm\]. The angular position of the second minima from the central maximum will be (in radians) [JEE Online 15-04-2018]

    A) \[\frac{\pi }{8}\]

    B) \[\frac{\pi }{12}\]

    C) \[\frac{\pi }{4}\]

    D) \[\frac{\pi }{6}\]

    Correct Answer: D

    Solution :

    [d] For single slit, the angular position is given as
    \[\sin \theta =\frac{n\lambda }{d}\]
    Here, \[n=2\]
    \[\sin \theta =\frac{2\times 550\times {{10}^{-9}}}{22\times {{10}^{-7}}}\]
    \[\sin \theta =\frac{1}{2}\]
    \[\theta =\frac{\pi }{6}\]


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