JEE Main & Advanced Physics Wave Optics / तरंग प्रकाशिकी JEE PYQ-Wave Optics

  • question_answer
    Unpolarized light of intensity I passes through an ideal polarizer A. Another identical polarizer B is placed behind A. The intensity of light beyond B is found to be\[\frac{\text{I}}{\text{2}}\]. Now another identical polarizer C is placed between A and B. The intensity beyond B is now found to be \[\frac{\text{I}}{8}\]. The angle between polarizer A and C is: [JEE Main Online 08-04-2018]

    A) \[45{}^\circ \]

    B) \[60{}^\circ \]

    C) \[0{}^\circ \]

    D) \[30{}^\circ \]

    Correct Answer: A

    Solution :

    [a] Polarizing axis of A & B polarizer are parallel to each other
    \[{{\text{I}}_{\text{1}}}\text{=}\frac{\text{I}}{\text{2}}\text{co}{{\text{s}}^{\text{2}}}\theta \]
    \[\frac{I}{8}={{I}_{1}}{{\cos }^{2}}\theta \]
    \[\frac{I}{8}=\frac{I}{2}{{\cos }^{4}}\theta \]
    \[\cos \theta =\frac{1}{\sqrt{2}}\]
    \[\]


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