question_answer

A ray of light is incident from a denser to a rarer medium. The critical angle for total internal reflection is \[{{\theta }_{iC}}\]and Brewster’s angle of incidence is \[{{\theta }_{iB}},\] such that \[\sin {{\theta }_{iC}}/\sin {{\theta }_{iB}}\]\[=\eta =1.28.\] = h = 1.28. The relative refractive index of the two media is:                                                   [JEE ONLINE 19-04-2014]

A) 0.2

B) 0.4

C) 0.8

D) 0.9

Correct Answer: C

Solution :

[c] Here,  As we know, where, is Brewster’s angle of incidence, and,  On solving we get, relative refractive index of the two media.