question_answer

The maximum number of possible interference maxima for slit separation equal to 1. 8A,, where X is the wavelength of light used, in a Young's double slit experiment is [JEE ONLINE 12-05-2012]

A) zero

B) 3

C) infinite

D) 5

Correct Answer: B

Solution :

[b] As and cannot be

or

Hence maximum number of possible interference maxim as,  i.e. 3