A) \[200{}^\circ C\]
B) \[270{}^\circ C\]
C) \[230{}^\circ C\]
D) \[250{}^\circ C\]
Correct Answer: C
Solution :
| [c] \[\Delta {{l}_{A}}=\Delta {{l}_{B}}\] |
| \[{{l}_{OA}}{{\alpha }_{A}}{{(\Delta T)}_{A}}={{l}_{OB}}{{\alpha }_{B}}{{(\Delta T)}_{B}}\] |
| \[\frac{\Delta T{{)}_{A}}}{{{(\Delta T)}_{B}}}=\frac{{{l}_{OB}}}{{{l}_{OA}}}\times \frac{{{\alpha }_{B}}}{{{\alpha }_{A}}}\] |
| \[\frac{180-30}{T-30}=1\times \frac{3}{4}\] |
| \[3T-90=600;T={{230}^{o}}C\] |
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