JEE Main & Advanced Physics Thermodynamical Processes JEE PYQ-Thermodynamical Processes

  • question_answer
    A diatomic gas with rigid molecules does 10 J of work when expanded at constant pressure. What would be the heat energy absorbed by the gas, in this process?                                  [JEE Main 12-4-2019 Afternoon]

    A)  35 J

    B)      40 J

    C)  25 J                

    D)       30 J

    Correct Answer: A

    Solution :

    [a] For a diatomic gas, \[{{C}_{p}}=\frac{7}{2}R\]
    Since gas undergoes isobaric process
    \[\Rightarrow \Delta Q=n{{C}_{p}}\Delta T\]
    Also,\[\Delta W=nR\Delta T=10J(given)\]
    \[\therefore \]\[\Delta Q=n\frac{7}{2}R\Delta T=\frac{7}{2}(nR\Delta T)=35J\]
     


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