JEE Main & Advanced Physics Thermodynamical Processes JEE PYQ-Thermodynamical Processes

  • question_answer
                A carnot freezer takes heat from water at \[^{o}C\] inside it and rejects it to the room at a temperature of \[{{27}^{o}}C\]. The latent heat of ice is\[336\times {{10}^{3}}J\,k{{g}^{-1}}\]. If 5 kg of water at \[{{0}^{o}}C\]is converted into ice at \[{{0}^{o}}C\]by the freezer, then the energy consumed by the freezer is close to:                                                                                         [JEE ONLINE 10-04-2016]

    A)  \[1.68\times {{10}^{6}}J\]      

    B)       \[1.71\times {{10}^{7}}J\]

    C)  \[1.51\times {{10}^{5}}J\]      

    D)       1\[1.67\times {{10}^{5}}J\]

    Correct Answer: D

    Solution :

    [d]
     
                heat required to freeze 5 kg water
    Joule
    for can not’s cycle
     


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