JEE Main & Advanced Physics Rotational Motion JEE PYQ-Rotational Motion

  • question_answer
    A smooth wire of length \[2\pi r\]is bent into a circle and kept in a vertical plane. A bead can slide smoothly on the wire. When the circle is rotating with angular speed \[\omega \]about the vertical diameter AB, as shown in figure, the bead is at rest with respect to the circular ring at position P as shown. Then the value of \[{{\omega }^{2}}\] is equal to :
    [JEE Main 12-4-2019 Afternoon]

    A)  \[\left( g\sqrt{3} \right)/r\]           

    B)       \[\frac{\sqrt{3}g}{2r}\]

    C)  \[2g/r\] 

    D)       \[2g/\left( r\sqrt{3} \right)\]

    Correct Answer: D

    Solution :

    [d]
                                        ….(1)
                                            ….(2)


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