A) \[6\times {{10}^{11}}\]
B) \[9\times {{10}^{11}}\]
C) \[11\times {{10}^{11}}\]
D) \[15\times {{10}^{11}}\]
Correct Answer: B
Solution :
[b] Given, ![]() ![]() |
and ![]() |
Intensity associated with each wavelength |
![]() ![]() |
work function ![]() ![]() |
![]() ![]() |
for different wavelengths |
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Work function for metallic surface ![]() ![]() |
Therefore, ![]() |
Now, no. of electrons per ![]() ![]() |
no. of electrons per |
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![]() ![]() |
So, the number of photo electrons liberated in 2 sec. |
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