A) \[{{10}^{-1}}\]
B) \[6\times {{10}^{-2}}\]
C) \[6\times {{10}^{2}}\]
D) \[3\times {{10}^{-3}}\]
Correct Answer: B
Solution :
| [b] The $ force is required for the circular motion of the body |
| Hence\[|F|=\frac{m{{v}^{2}}}{r}\] |
| \[\frac{m{{v}^{2}}}{r}=\frac{16}{r}+{{r}^{3}}\] |
| \[m{{v}^{2}}=16+{{r}^{4}}\] |
| K.E. \[=\frac{m{{v}^{2}}}{2}=8+\frac{{{r}^{4}}}{4}\] |
| Putting the value of\[r=1\]and \[r=4\]taking the ratio |
| We get the\[\approx 6\times {{10}^{-2}}\] |
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