A) \[\sqrt{3}\] W
B) W
C) \[(\sqrt{3}/2)\]W
D) 2 W
Correct Answer: A
Solution :
[a] As the work \[W=MB\,(1-\cos \theta )\] |
\[\Rightarrow \] \[W=MB\,(1-\cos \,{{60}^{o}})\] \[(\because \theta ={{60}^{o}})\] |
\[\Rightarrow \] \[W=\frac{MB}{2}\] |
\[\therefore \] MB = 2 W |
Torque, \[\tau =MB\sin {{60}^{o}}\] |
\[=\frac{MB\sqrt{3}}{2}=\frac{2W\sqrt{3}}{2}=W\sqrt{3}\] |
You need to login to perform this action.
You will be redirected in
3 sec