A) 6.98 s
B) 8.76 s
C) 6.65 s
D) 8.89 s
Correct Answer: C
Solution :
[c] \[T=2\pi \sqrt{\frac{I}{MB}}\] |
\[I=7.5\times {{10}^{-6}}kg-{{m}^{2}}\] |
\[M=6.7\times {{10}^{-2}}A{{m}^{2}}\] |
By substituting value in the formula |
\[T=.665\,\sec \] |
for 10 oscillation, time taken will be |
Time = 10 T = 6.65 sec |
Answer option 3 |
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