A) s \[1\times {{10}^{5}}{{m}^{2}}\]
B) \[5\times {{10}^{5}}{{m}^{2}}\]
C) \[2\times {{10}^{5}}{{m}^{2}}\]
D) \[5\times {{10}^{4}}{{m}^{2}}\]
Correct Answer: B
Solution :
[b] |
\[{{A}_{1}}{{\text{v}}_{1}}={{A}_{2}}{{\text{v}}_{2}}\] |
\[{{10}^{-4}}\times 1={{A}_{2}}{{\text{v}}_{2}}\] |
\[{{A}_{2}}{{\text{v}}_{2}}={{10}^{-4}}\] .(1) |
\[P+\frac{1}{2}\rho (v_{1}^{2}-v_{2}^{2})+\rho gh=P\] |
\[v_{2}^{2}=v_{1}^{2}+2gh\] |
\[v_{2}^{{}}=\sqrt{\text{v}_{1}^{2}+2gh}\] |
\[=\sqrt{1+2\times 10\times 0.15}\] |
\[\frac{{{10}^{-4}}}{{{A}_{2}}}=2\] |
\[{{A}_{2}}=5\times {{10}^{-5}}{{m}^{2}}\] |
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