A) \[2.535\times {{10}^{3}}\Omega \]
B) \[4.005\times {{10}^{3}}\Omega \]
C) \[1.985\times {{10}^{3}}\Omega \]
D) \[2.045\times {{10}^{3}}\Omega \]
Correct Answer: C
Solution :
[c] \[10=(5\times {{10}^{-3}})(15+R)\] \[r=1985\,\Omega \]
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