question_answer

In a Wheatstone’s bridge, three resistances P, Q and R are connected in the three arms and the fourth arm is formed by two resistances\[{{S}_{1}}\]and\[{{S}_{2}}\]connected in parallel. The condition for the bridge to be balanced will be      [AIEEE 2006]

A) \[\frac{P}{Q}=\frac{2R}{{{S}_{1}}+{{S}_{2}}}\]

B) \[\frac{P}{Q}=\frac{R({{S}_{1}}+{{S}_{2}})}{{{S}_{1}}{{S}_{2}}}\]

C) \[\frac{P}{Q}=\frac{R({{S}_{1}}+{{S}_{2}})}{2{{S}_{1}}{{S}_{2}}}\]

D) \[\frac{P}{Q}=\frac{R}{{{S}_{1}}+{{S}_{2}}}\]