| In an experiment, the resistance of a material is plotted as a function of temperature (in some range). As shown in the figure, it is a straight line. One may conclude that : [JEE Main 10-4-2019 Morning] |
 |
A) \[R(T)=\frac{{{R}_{0}}}{{{T}^{2}}}\]
B) \[R(T)={{R}_{0}}{{e}^{-{{T}^{2}}/T_{0}^{2}}}\]
C) \[R(T)={{R}_{0}}{{e}^{-T_{0}^{2}/T_{{}}^{2}}}\]
D) \[R(T)={{R}_{0}}{{e}^{T_{{}}^{2}/T_{0}^{2}}}\]
Correct Answer: C
Solution :
 |
 |
  |
You need to login to perform this action.
You will be redirected in
3 sec
