A) \[{{v}^{2}}\]
B) \[1/m\]
C) \[1/{{v}^{4}}\]
D) \[1/Ze\]
Correct Answer: B
Solution :
[b] At the distance of closest approach, the total kinetic energy of particle will must be converted into potential energy. |
Since, nuclear target is heavy, it can be assumed safely that it will remain stationary and will not move due to the coulombic interaction force. |
At distance of closest approach, relative velocity of two particles is v. Here, target is considered as stationary, so-particle comes to rest instantaneously at distance of closest approach. Let ' required distance be r, then from work-energy theorem, |
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