A) \[1.6\times {{10}^{14}}\]
B) \[7.8\times {{10}^{14}}\]
C) \[5.6\times {{10}^{12}}\]
D) \[6.2\times {{10}^{15}}\]
Correct Answer: B
Solution :
| [b] \[T\,\,\alpha \,\,{{n}^{3}}\] |
| \[\therefore {{T}_{2}}=8T=8\times 1.6\times {{10}^{16}}s\] |
| \[\therefore v=\frac{1}{{{T}_{2}}}=\frac{1}{8\times 1.6\times {{10}^{16}}}\] |
| \[\approx 7.8\times {{10}^{14}}Hz\] |
You need to login to perform this action.
You will be redirected in
3 sec
