A) \[1.6\times {{10}^{14}}\]
B) \[7.8\times {{10}^{14}}\]
C) \[5.6\times {{10}^{12}}\]
D) \[6.2\times {{10}^{15}}\]
Correct Answer: B
Solution :
[b] \[T\,\,\alpha \,\,{{n}^{3}}\] |
\[\therefore {{T}_{2}}=8T=8\times 1.6\times {{10}^{16}}s\] |
\[\therefore v=\frac{1}{{{T}_{2}}}=\frac{1}{8\times 1.6\times {{10}^{16}}}\] |
\[\approx 7.8\times {{10}^{14}}Hz\] |
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