A) \[20eV\]
B) \[79eV\]
C) \[109eV\]
D) \[34eV\]
Correct Answer: B
Solution :
[b] Let |
\[{{E}_{1}}=\]energy required to remove |
\[{{e}^{-}}\] |
from singly ionised Helium atom |
\[=\frac{+13.6{{z}^{2}}}{{{n}^{2}}}\] |
\[=\frac{(13.6){{(2)}^{2}}}{{{(1)}^{2}}}\] |
\[=54.4eV\] |
\[{{E}_{2}}=\] Energy required to remove an \[{{e}^{-}}\] from He atom |
Given \[{{E}_{1}}=2.2{{E}_{2}}\] |
\[\therefore {{E}_{2}}=\frac{{{E}_{1}}}{2.2}=\frac{54.4}{2.2}=24.7eV\] |
\[\therefore \] Energy required to remove both \[{{e}^{-}}'s\] from He-atom |
\[=24.7+54.4\] |
\[=79.1eV\] |
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