question_answer

A hydrogen atom makes a transition from n = 2 to n=1 and emits a photon. This photon strikes a doubly ionized lithium atom (z = 3) in excited state and completely removes the orbiting electron. The least quantum number for the excited stated of the ion for the process is: [JEE ONLINE 09-04-2016]

A) 4

B) 5

C) 2

D) 3

Correct Answer: A

Solution :

[a] Energy of proton = 13.6 . 3.4 = 10.2eV

For removal of electron

so minimum value of n = 4